Skip to main content
Solved

Huygens MTF的截止頻率

  • December 3, 2021
  • 1 reply
  • 435 views

Sean.Lin
Zemax Staff
Forum|alt.badge.img+1

下圖為Zemax範例Cooke的FFT MTF和Huygens MTF,FFT MTF的截止頻率為370左右,可由1/(lambda*F/#)計算出。但想要請問Huygens MTF的截止頻率1452該如何計算?

 

Best answer by Sean.Lin

Help File裡面的確是沒有寫到Huygens MTF的截止頻率計算方式。MTF的截止頻率是直接跟PSF的取樣間隔相關,在Huygens PSF中可以自己指定間隔 (Delta)。截止頻率就是單純取倒數然後再除以2乘1000,如下圖所示。

至於原始Image Delta = 0的話,Default 的delta如底下所示

 

View original
Did this topic help you find an answer to your question?

1 reply

Sean.Lin
Zemax Staff
Forum|alt.badge.img+1
  • Author
  • Zemax Staff
  • 54 replies
  • Answer
  • December 3, 2021

Help File裡面的確是沒有寫到Huygens MTF的截止頻率計算方式。MTF的截止頻率是直接跟PSF的取樣間隔相關,在Huygens PSF中可以自己指定間隔 (Delta)。截止頻率就是單純取倒數然後再除以2乘1000,如下圖所示。

至於原始Image Delta = 0的話,Default 的delta如底下所示

 


Cookie policy

We use cookies to enhance and personalize your experience. If you accept you agree to our full cookie policy. Learn more about our cookies.

 
Cookie settings