I want to know the detail about how thermal pick up values being calculatedin in multi-configuration editor for coefficients of even asphere surface.
The surface sag is given by:
I can find related information from helpfile:
Values in multi-configuration shown as below, surface 7 is even asphere surface, TCE for surf7 is 8, TEMP for configuration 1,2, 3 is 20, 60, 100, respectively. The first configuration is the nominal configuration:
How thermal pickup values being calculated?
Best answer by Julia
Answer:
For coefficients of Even Asphere surface, a1, a2, a3… they have different units, and shown as below in case of lens units was mm :
a1, units was 1/mm
a2, units was 1/mm^3
a3, units was 1/mm^5
……
So the scaling for above parameters was 1/r, 1/r^3, 1/r^5 ….
The TCE value is the thermal coefficient of expansion in 1e-6/K. We know that TCE=8, and δT=40 K. a1=a2=a3=p=100
Radius of surface7 is 100.
For configuration2:
radius= 100+100*8*40*e-6= 100.032
crvt= 1/100.032= 9.996801024E-03
a1= p/(scale of r) = p/(100.032/100)= 0.9996810 p
a2=p/scale of (r^3)= p/ (100.032^3/100^3)= 0.99904614 p
a3=p/ scale of (r^5))=p/(100.032^5/100^5)= 0.99840153 p
For configuration3:
radius= 100+100*8*80*e-6= 100.064
crvt= 1/100.064= 9.993604093E-03
a1= p/(scale of r) = p/(100.064/100)= 0.9993604093 p
a2=p/scale of (r^3)= p/ (100.064^3/100^3)= 0.998082455 p
a3=p/ scale of (r^5))=p/(100.064^5/100^5)= 0.9968061348 p
For coefficients of Even Asphere surface, a1, a2, a3… they have different units, and shown as below in case of lens units was mm :
a1, units was 1/mm
a2, units was 1/mm^3
a3, units was 1/mm^5
……
So the scaling for above parameters was 1/r, 1/r^3, 1/r^5 ….
The TCE value is the thermal coefficient of expansion in 1e-6/K. We know that TCE=8, and δT=40 K. a1=a2=a3=p=100
Radius of surface7 is 100.
For configuration2:
radius= 100+100*8*40*e-6= 100.032
crvt= 1/100.032= 9.996801024E-03
a1= p/(scale of r) = p/(100.032/100)= 0.9996810 p
a2=p/scale of (r^3)= p/ (100.032^3/100^3)= 0.99904614 p
a3=p/ scale of (r^5))=p/(100.032^5/100^5)= 0.99840153 p
For configuration3:
radius= 100+100*8*80*e-6= 100.064
crvt= 1/100.064= 9.993604093E-03
a1= p/(scale of r) = p/(100.064/100)= 0.9993604093 p
a2=p/scale of (r^3)= p/ (100.064^3/100^3)= 0.998082455 p
a3=p/ scale of (r^5))=p/(100.064^5/100^5)= 0.9968061348 p
What’s the equation for surface shape versus temperature in a sequential code? As it turns out, the equation is in the attached pdf with an explination, it is derived from the realization that the part expands and contracts, while the coordinate system does not. Not sure if this was published by anybody, I worked it out myself in 1986.
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