I think I am not understanding something about how the optimization operands OPTH and/or OPDC are calculated.
For example, if I set up a first OPTH to calculate for the image surface and Py = 1, then a second OPTH also for the image surface but with Py = 0, then shouldn’t the difference between the values of those two operands, when divided by the wavelength (with the conversion from microns to millimetres), give the same value as an OPDC operand with Py = 1?
The OPDC operand calculates the system OPD (relative to the chief ray). It is measured with respect to the exit pupil reference sphere. See the “Exit Pupil” topic in the help documentation:
Regards,
Jeff
Thanks,
(I totally missed that bit re: exit pupil.)
Enter your E-mail address. We'll send you an e-mail with instructions to reset your password.
Do not provide any information or data that is restricted by applicable law, including by the People’s Republic of China’s Cybersecurity and Data Security Laws ( e.g., Important Data, National Core Data, etc.).
不要提供任何受适用法律，包括中华人民共和国的网络安全和数据安全法限制的信息或数据（如重要数据、国家核心数据等）。