Skip to main content

Can you confirm that when computing the Fft Mtf with “All” wavelenghts, the resulting MTF is the weighted average of all individual monochromatic MTF ?

The doc only mentions “Wavelength The wavelength number to be used in the calculation.”, but does not explicitely states what happens if “All” is selected 

@mocquin 

 

This might be helpful:

More specifically, if you look at ​@Jeff.Wilde’s answers. It seems that:

if you compute the weighted average of the complex OTF functions, then take the magnitude, you will find the same polychromatic MTF result that OpticStudio calculates

Which Jeff verified:

Take care,

 

David

 


Reply