Can you confirm that when computing the Fft Mtf with “All” wavelenghts, the resulting MTF is the weighted average of all individual monochromatic MTF ?
The doc only mentions “Wavelength The wavelength number to be used in the calculation.”, but does not explicitely states what happens if “All” is selected
Best answer by David.Nguyen
This might be helpful:
More specifically, if you look at
if you compute the weighted average of the complex OTF functions, then take the magnitude, you will find the same polychromatic MTF result that OpticStudio calculates
Which Jeff verified:
Take care,
David
+2
This might be helpful:
More specifically, if you look at
if you compute the weighted average of the complex OTF functions, then take the magnitude, you will find the same polychromatic MTF result that OpticStudio calculates
Which Jeff verified:
Take care,
David
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