Skip to main content
Solved

How does OpticStudio define the s- and p-polarization states?

  • February 14, 2019
  • 1 reply
  • 1023 views

Allie
Zemax Staff
Forum|alt.badge.img+2
  • Zemax Staff
  • 340 replies

What are the s- and p-polarization states? How do I make my incoming beam s-polarized?

 

Best answer by Allie

A common misconception is that a ray itself (or beam of light) is s- or p- polarized. S and p are not inherent to an incoming beam of light, but are instead defined relative to the plane of incidence of the ray on a surface.

The amplitude and polarization state of the electric field is described by a vector E which has components {Ex, EyEz} which are all complex-valued. The ray propagation vector k has components {l, m, n} where l, m, and n are the direction cosines of the ray in the x, y and z directions. The electric field vector E must be orthogonal to the propagation vector k so that:

And, therefore:

What we choose to call the x, y and z axes is arbitrary. For example, I may choose z to go from left to right across the screen, y from bottom to top, and x into the screen. Or, I might choose z to point out of the screen, y to go left to right and x to go bottom to top. As long as I am consistent in my definition of coordinate axes, there is no problem.

But, when a ray intercepts the surface of an optical component, we define a plane, called the plane of incidence, which is not arbitrary. The plane of incidence contains both the k vector and the surface normal vector n at the intercept point. The s-component of the field is the projection of E that lies along the axis orthogonal to the plane of incidence, while the p-projection lies within the plane of incidence. The electric field E is then divided into Es and Ep components, both of which are complex-valued.

So, s and p are defined relative to the plane of incidence of the ray on the surface, and are not characteristics of the beam itself.

View original
Did this topic help you find an answer to your question?

1 reply

Allie
Zemax Staff
Forum|alt.badge.img+2
  • Author
  • Zemax Staff
  • 340 replies
  • Answer
  • February 14, 2019

A common misconception is that a ray itself (or beam of light) is s- or p- polarized. S and p are not inherent to an incoming beam of light, but are instead defined relative to the plane of incidence of the ray on a surface.

The amplitude and polarization state of the electric field is described by a vector E which has components {Ex, EyEz} which are all complex-valued. The ray propagation vector k has components {l, m, n} where l, m, and n are the direction cosines of the ray in the x, y and z directions. The electric field vector E must be orthogonal to the propagation vector k so that:

And, therefore:

What we choose to call the x, y and z axes is arbitrary. For example, I may choose z to go from left to right across the screen, y from bottom to top, and x into the screen. Or, I might choose z to point out of the screen, y to go left to right and x to go bottom to top. As long as I am consistent in my definition of coordinate axes, there is no problem.

But, when a ray intercepts the surface of an optical component, we define a plane, called the plane of incidence, which is not arbitrary. The plane of incidence contains both the k vector and the surface normal vector n at the intercept point. The s-component of the field is the projection of E that lies along the axis orthogonal to the plane of incidence, while the p-projection lies within the plane of incidence. The electric field E is then divided into Es and Ep components, both of which are complex-valued.

So, s and p are defined relative to the plane of incidence of the ray on the surface, and are not characteristics of the beam itself.


Reply


Cookie policy

We use cookies to enhance and personalize your experience. If you accept you agree to our full cookie policy. Learn more about our cookies.

 
Cookie settings