If I have a 2D array e.g. 10x2 A(x,y), what’s the syntax to extract one column (or row) in that array so that it’s a 1D array?
I’ve tried:
col = A(1:10,3)
col = A(:,3)
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Unfortunately, ZPL doesn’t support slicing as you have tried as far as I know. Instead, you will have to do the slicing inside a loop. Something like so:
DECLARE an_array, INTEGER, 2, 10, 2
FOR jj, 1, 2, 1
FOR ii, 1, 10, 1
an_array(ii, jj) = ii + (jj-1)*10
NEXT
NEXT
DECLARE a_vector, INTEGER, 1, 10, 1
jj = 2
FOR ii, 1, 10, 1
a_vector(ii) = an_array(ii, jj)
NEXT
FOR ii, 1, 10, 1
PRINT a_vector(ii)
NEXT
RELEASE a_vector
RELEASE an_arrayIf you require more advanced programming features, I strongly suggest to look into the ZOS-API.
Take care,
David
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