Hi Adrian,

The 'coating-transmission vs angle' is modeling the transmission of the surface, including the effect of any coatings. In this case, the dominant loss is the Fresnel reflection from the air-glass interface. It considers only the surface; bulk absorptions by a thickness is not modeled. The result is the expected ( (n2-n1)/(n1+n2) )^2 for transmission at normal incidence.

In the sequential model, the losses include the effects of bulk absorption (in this case negligible) and the Fresnel reflections at both the entrance (air-glass) and exit (glass-air) interfaces. Since absorption is negligible and transmission near unity, the total transmission is well approximated by the square of the surface transmission, which is what OpticStudio is reporting.

Kind regards,

David

Hi David,

Thank you for your fast response.   It is not clear for me it is the results of the detector after the BK7.  I have a detector before the BK7 which detects 100W total power and a detector after the BK7 window.   The detector after BK7 it  is measuring 91.7%.  ( 91.7W ).  What is the meaning of the value?   I expected to be the transmsion, as you explain, approximatably the square of surface transmisison. 

H Adrian,

Here is what I think you have modeled:

It is a BK7 window with a single ray passing through it to a detector. I offset the window so the line in the cylinder is not confused with the ray. The ray passes through two glass-air interfaces on the way to the window.

In the layout below I tilted the window 10 degrees so we could see the Fresnel reflections.

The rrays traced are limited to those with a relative intensity of 0.001 of the original ray, But we see the beginning of the infinite cascade of internal reflections. In the layout below the limit is set to 0.01 so we just see the most significant.losses:

If we consider the original non-tilted case. The transmission through the first surface into the window is 0.9578 as determined by the 'transmission vs wavelength' analysis. This represents a reflection of about 4%. The the transmitted ray then encounters a second glass-air interface as it exits the window. That will also transmit 0.9578. So discounting bulk absorption -- which is negligible -- the total transmission through the window will be o.9578 x 0.9578 = 0.9174.

When I send a 1 watt ray through the window I get 0.9173 measured by the detector.

Kind regards,

David

Hi David,

I see my mistake, I thought  that the transmisison vs angle is the object transmission..

Thank you for your assitance.

Best Regards,

Adrian